Pointer magic
2007-11-20 21:42The following C type definition can be used for declaring local and global structure objects. You can initialize them as if they were bare structures, because C doesn't mind if you omit curly brackets in initializers (though gcc -Wall will complain). You can also use the typedef to declare function arguments, in which case the function will expect a pointer to the structure instead of a copy of it. Furthermore, when you use a variable declared with this typedef, it will be quietly converted into a pointer to the structure just as is expected by the function. This avoids a load of & operators and gives you a sort of poor-man's C++ pass-by-reference.
typedef struct mytype {
/* member declarations */
} mytype[1];
mytype var;
int func(mytype arg);
func(var);
ETA: it seems this trick is used by GMP (see the last paragraph of that page)
[Poll #1092168]
no subject
Date: 2007-11-21 05:20 (UTC)no subject
Date: 2007-11-21 09:09 (UTC)Also if you want to define a more complex type with one of these things as its base type, it's hard to work out how. When I was working with GMP a while back I occasionally wanted to write a function which took a pointer to an array of
mpf_t; I managed it in the end by just adding or removing*s until the compiler stopped complaining, but I wouldn't say I understand the syntactic rules which make the right answer right and the wrong ones wrong. (And, just to put that in perspective, I do feel that I understand pretty much all the rest of the C declarator syntax, which I know isn't a statement all C programmers could make!)no subject
Date: 2007-11-21 10:19 (UTC)